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anzhelika [568]
2 years ago
10

The function f(x) = x2 6x 3 is transformed such that g(x) = f(x − 2). find the vertex of g(x). (−1, −8) (−3, −4) (−1, −6) (−5, −

6)
Mathematics
1 answer:
timama [110]2 years ago
3 0

Answer: (-1,-6)

Step-by-step explanation:

x^2+6x+3

g(x) = f(x-2)

replace all value of x in the f(x) function to (x-2)

(x-2)^2 + 6(x-2) + 34

(x-2)(x-2) + 6(x-2) + 34

expand through FOIL and distribution

x^2-4x+4+6x-12+3

combine like terms

x^2+2x-5

-b/2a = x value of vertex

-2/2(1) = x value

x value = -1

plug in -1 for all values of x in the g(x) equation to solve for y value

(-1)^2+2(-1)-5

1-2-5 = -6

y = -6

x = -1

(x,y) = (-1,-6)

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3 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
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Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

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                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

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Answer:

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If you input the 975 and take 15 percent away you would get 828.75

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