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alisha [4.7K]
3 years ago
5

The length, breadth and height of a rectangular room are in the ratio of 3:2:1. If the room contains 3072 cubic meter of air, fi

nd the length, breadth and height of the room.​
Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer:

  • length: 24 m
  • breadth: 16 m
  • height: 8 m

Step-by-step explanation:

Let k represent the multiplier of the ratio units that will give actual dimensions. The the height can be represented by k, the breadth by 2k, and the length by 3k. The volume of the room will be ...

  V = LBH

  V = (3k)(2k)(k) = 6k³

  3072 m³ = 6k³ . . . . . use known volume

  512 m³ = k³ . . . . . . . divide by 6

  8 m = k . . . . . . . . . take the cube root

The height of the room is 8 m, its breadth is 16 m, and its length is 24 m.

Andru [333]3 years ago
3 0

Answer:

See below ↓↓↓

Step-by-step explanation:

<u>Given</u> :

  • Length, breadth, and height in the ratio 3 : 2 : 1
  • Room contains 3072 cubic meter of air [refers to volume]

<u>Solving</u> :

  • Let the length, breadth, and height be 3x, 2x, and x respectively
  • Multiply them and equate to the volume
  • (3x)(2x)(x) = 3072
  • 6x³ = 3072
  • x³ = 512
  • x = 8

<u>Solution</u> :

  • <u>Length = 3x = 24 m</u>
  • <u>Breadth = 2x = 12 m</u>
  • <u>Height = x = 8 m</u>
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Answer:

ME = 1.761* \frac{5}{\sqrt{15}}=2.273

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 75 represent the sample mean for the sample  

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Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that t_{\alpha/2}=1.761

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ME = 1.761* \frac{5}{\sqrt{15}}=2.273

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