10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
Answer:
The final speed of bicycle would be <u>27 m/s</u>².
Step-by-step explanation:
<u>Given</u> :
Initial velocity (u) = 15 m/s
Acceleration (a) = 3.0 m/s²
Time = 4 seconds
<u>To</u><u> </u><u>Find</u> :
Final velocity (v)
<u>Using</u><u> </u><u>Formula</u> :

v = final velocity
u = initial velocity
a = acceleration
t = time taken
<u>Solution</u> :
Substituting the values in the formula to find the final velocity :







Hence, the final speed of bicycle would be 27 m/s².

Answer:
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The point
is on the graph.
<h3>Procedure - Inverse variation</h3><h3 /><h3>Inverse variation model</h3><h3 />
An <em>inverse</em> variation is represented by the following formula:
(1)
Where:
- Independent variable.
- Dependent variable.
- Proportionality constant.
We can eliminate the proportionality constant by creating the following relationship:
(2)
<h3>Determination of another point</h3>
If we know that
,
and
, then the remaining variable is:


The point
is on the graph. (Correct choice: C) 
To learn more on inverse variations, we kindly invite to check this verified question: brainly.com/question/4838941
<h3>Remark</h3>
The statement is incomplete. Complete form is described below:
<em>Point </em>
<em> is on the graph of an inverse variation. Which of the following ordered pair is on the graph? </em><em>A.</em><em> </em>
<em>, </em><em>B.</em><em> </em>
<em>, </em><em>C.</em><em> </em>
<em>, </em><em>D.</em><em> </em>
<em>.</em>