For an ellipse, the foci lie on a line called the

ValentinkaMS [17]

that is whysjjsnsjs

i am dum

6 0

3 years ago

In 1848 rioting in Berlin forced the Prussian king to do what

marin [14]

To promise a constitution

3 0

3 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

The proportion of Good TV set is 0.67
The number of ways of selecting 5 from 6 TV sets is 6
The number of ways of selecting 4 from 6 TV sets is 15

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

(a) Proportion that are good

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

(b) Ways to select 5 samples (without replacement)

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

(c) All possible sample space of 4

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

(d) The sampling distribution

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

3 0

3 years ago

What does the “conflict” in conflict theory signify?

AfilCa [17]

It is C. because Face due to labor strikes

8 0

3 years ago

As the price of gummy bears rises from $2. 60 to $3 , what are the price elasticities of demand of sugar-free gummy bears and of

NISA [10]

The price elasticities of demand of sugar-free gummy bears and of ordinary gummy bears is -0.8 and -2.3 respectively.

<h3>How to calculate price elasticity</h3>

Change in price of gummy bears = $2. 60 to $3

Elasticity of demand of sugar-free gummy bears =

[(273-379 / (273+379)/2] ÷ [(3.00-2.60)/(3.00+2.60) / 2]

= [-18/166] / [0.4/2.8]

= -0.10843373493975 / 0.14285714285714

= - 0.75903614457826

Approximately, -0.8

Elasticity of demand of regular gummy bears:

Sugar free = [(273-379) / (273+379)/2] ÷ (3.00 +2.60) / 2]

= [-106/326] / [0.4/2.8]

= -0.32515337423312 / 0.14285714285714

= -2.2760736196318

Approximately, -2.3

Learn more about price elasticity:

brainly.com/question/24961010

7 0

2 years ago

For an​ ellipse, the foci lie on a line called the

For an ellipse, the foci lie on a line called the