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BlackZzzverrR [31]
2 years ago
15

Which ames are other ways to name <1?

Mathematics
1 answer:
san4es73 [151]2 years ago
8 0

Answer: <PFY

<YFP

<F

Step-by-step explanation:

You might be interested in
28 -4t = 3t is it 4 the answer
antiseptic1488 [7]

Answer:

Yes!

Step-by-step explanation:

28 - 4t = 3t

Isolate t:

28 = 7t

t = 28 / 7 = 4

4 0
3 years ago
Read 2 more answers
If Log 20 = 1.301 what is the value of Logsub100 20?
Charra [1.4K]

Answer:

log_{100}20 = 0.6505

Step-by-step explanation:

log20 = 1.301 (when you see only "log" with no base, it is taken as a base 10)

This basically means:

10^{1.301} = 20  (This is the log in exponential form)

Since we don't know what  log_{100}20  is equal to, we will say  log_{100}20 = x

So to solve for log_{100}20 = x, you do the same thing. (convert to exponential form)

100^{x} =20

Now you will notice that both of these equations are equal to 20.

Since 20 = 20,

we can say 100^{x} = 10^{1.301}

Another way of saying 100, is 10^{2} (make the bases the same)

Now we get 10^{2x} = 10^{1.301}      

(we get 2x because an exponent to the power of an exponent (2^{x}) is the same as 2 * x)

Because you have the same base, you can just ignore the 10s and focus on the exponents. So you get:

2x = 1.301

x = 0.6505

6 0
3 years ago
(06.01 LC)
disa [49]
No association would be the answer.

6 0
3 years ago
Read 2 more answers
Need help quickly! Thanks
Rzqust [24]

Answer:

y = -2^x

Step-by-step explanation:

If the equation of a function is in the form of y = h(x)

When the graph of this function is reflected across x-axis,

Transformed function will be,

y = -h(x)

Further reflected across y-axis, then the transformed function will be,

y = -h(-x)

By this rule,

Given equation when reflected across x-axis,

y = -(\frac{1}{2})^{x}

Further reflected across y-axis,

y = -(\frac{1}{2})^{-x}

y = -(2^{-1})^x

y = -2^x

5 0
3 years ago
3x^2+ 4x + 5 for x = -2
Alexus [3.1K]
The answer is 33
3(-2)^2+4(-2)+5
-6^2+ (-8) + 5
36 + (-8) + 5
28+5
33
7 0
3 years ago
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