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frozen [14]
2 years ago
12

Is 336 − –5,083 positive or negative?

Mathematics
2 answers:
Vesna [10]2 years ago
3 0

Answer:

positive

Step-by-step explanation:

if you subtract a negative number, it’s the same as adding a positive number. If you add 2 positive numbers, you get a positive number, so the expression is positive.

pashok25 [27]2 years ago
3 0

Answer:

<u><em>negative</em></u>

Step-by-step explanation:

===============================================================

<u><em>have a great weekend!</em></u>

<u><em></em></u>

<u><em>can i have brainiest answer please?</em></u>

<u><em></em></u>

<u><em>=================================================================</em></u>

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11 halves divided by 7
Tamiku [17]

Answer:

\large\boxed{\dfrac{11}{14}}

Step-by-step explanation:

\dfrac{\frac{11}{2}}{7}=\dfrac{11}{2}\div7=\dfrac{11}{2}\div\dfrac{7}{1}=\dfrac{11}{2}\cdot\dfrac{1}{7}=\dfrac{(11)(1)}{(2)(7)}=\dfrac{11}{14}

4 0
4 years ago
Read 2 more answers
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
100 Points!!!
Mars2501 [29]

Let's see

#a

Take 28

  • (28)²
  • (30-2)²
  • 30²-2(30)(2)+2²
  • 900-120+4
  • 780+4
  • 784

#2

Take 9,10

  • 9³+10³
  • (9+10)(9²-9×10+10²)
  • (19)(81-90+100)
  • 19(181-90)
  • 19(91)
  • 1729
7 0
2 years ago
Read 2 more answers
Algebra problem, please show work!
Brrunno [24]

6x+1 / 2x +6 - 5/2

Factor 2 out of the denominator of the first fraction:

6x+1 / 2(x+3) - 5/2

Rewrite 5/2 to have a common denominator with the first fraction:

6x+1/2(x+3) - 5(x+3) / 2(x+3)

Simplify terms:

6x +1 - 5(x+3) / 2(x+3)

Use distributive property:

6x +1 - 5x -15 / 2(x+3)

Combine like terms for final answer:

(x-14) / 2(x+3)

4 0
3 years ago
00:00
Zigmanuir [339]

Answer:

c   and d

Step-by-step explanation:

i think

4 0
3 years ago
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