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3 years ago

1/3 of a number is 17, what is the number?

Mathematics

2 answers:

Keith_Richards [23]3 years ago

4 0

Multiply 17 x 3 to find the original number which is 51
then to check it you can divide 51 by 3 and you should get 17

Nastasia [14]3 years ago

3 0

You can either add 17+17+17 which would be 51 or if you would rather use multiplication you could do 17x3 which would be 51 also. I hope this helps some and have a good day!

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3. Paula commutes 60 km each day for work, five days a week, nine months of the year. She travels 720

bezimeni [28]

Answer:

16,080 km.

Step-by-step explanation:

We want the total number of kilometers in one year.

4 weeks /month.

for Work: 9 months in the year 60 km/day 5 days/week

Family Visit : 720 km for 4 times a year

Personal: 200 km / month

Work total = 60 km/day * 5 days/week * 4week/month * 9 months

WorkTotal= 60*5*4*9 = 10,800 km

FamilyTotal= 4*720 = 2880 km

Personal = 200*12 = 2400 km

Total = 10,800 + 2880 + 2400 = 16,080 km

7 0

4 years ago

Any number that is divisible by 3 is divisible by nine

vovangra [49]

I think what you are trying to ask is what number is divisible by three and nine
multiply 3 and 9 to get your answer
= 27
27 because it can be divided by 3 and = 9 and can be divided by 9 and = 3

5 0

3 years ago

Read 2 more answers

Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property Power Rule of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

3 0

3 years ago

Velma must make five bottles of lemonade for the kids playing outside. Each bottle requires 3⁄4 cup of sugar. How much sugar doe

Ket [755]

The total number of cups of sugar needed will be given by:
Total amount=(number of bottles)×(number of cups of sugar per box)
number of bottles to be made is 5 bottles
number of cups per box is 3/4
thus the total number of cups required will be:
Total amount=3/4×5=3 3/4 cups

6 0

3 years ago

Use inductive reasoning to describe the pattern. Then find the next two numbers in the pattern. 1, 4, 7, 10, . . .

Colt1911 [192]

The reasoning would be that the pattern is going up by 3 every time. 13, 16

5 0

3 years ago