Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
= (4 * 12) inches
= 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
= (3/4) * 48 inches
= 3 * 12 inches
= 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
= 84 inches
So Jack and Christine together crawled a distance of 84 inches.
Add up the fractional amounts and divide them by however many amounts there are..........
eg.
Step 1:Add the fractions
1/6 + 5/8 +3/4
(find the LCD)
1/6 + 5/8 + 3/4 = 4/24 + 15/24 + 18/24 = 37/24
Step 2: Divide the sum by the number of numbers in the set
37/24 ÷ 3= 37/24 ÷ 3/1= 37/24 X 1/3= 37/72
<span>So the mean (average) is 37/72</span>
Answer:
3 because your domain should not repeat
