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Katen [24]
2 years ago
12

1/4*3/4=what is the answer​

Mathematics
1 answer:
-Dominant- [34]2 years ago
7 0

Answer:

3 over 8

3

8

=0.375

Step-by-step explanation:

You might be interested in
Simplify -4(x+6)+2(x-2)
kati45 [8]

Answer:

-2x-28

Step-by-step explanation:

We can apply the distributive property then combine like terms for a simpler equation.

-4(x+6)+2(x-2)\\\\-4x-24+2x-4\\\\-2x-28

Hope this helped!

6 0
3 years ago
Read 2 more answers
Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
4 years ago
A 6-pack of undershirts cost 13.98.This is 3.96 less then the cost of buying 6 individual shirts.If each undershirt costs the sa
mihalych1998 [28]
1.67 is your answer 13.98 - 3.96=10.02 10.02 divided by 6 = 1.67
Hope I helped
8 0
3 years ago
X + 25/-8 = -6 Solve for x.<br> Simplify your answer as much as possible.
balandron [24]

Step-by-step explanation:

if there is nothing missing, we have

x + 25/-8 = -6

in order to compare or add or subtract fractions, we need to bring them all to the same denominator (bottom part).

remember, integer numbers are fractions too. like here

-6 = -6/1

25/-8 = -25/8

so, how can we bring -6/1 to .../8 ?

by multiplying 1 by 8.

but we cannot multiply only the denominator by 8. otherwise we would suddenly have

-6/8

and is -6/8 = -6/1 ? no, certainly not.

to keep the original value of the fraction we have to do the same multiplication also with the numerator (top part).

so, we actually do

-6/1 × 8/8 = -48/8

with this little trick we have now .../8 to operate with, and our transformed fraction has still the same value

-6/1 = -48/8 indeed.

so, we have

x + -25/8 = -48/8

x - 25/8 = -48/8

x = -48/8 + 25/8 = -23/8

3 0
2 years ago
A construction crew is lengthening a road. The road started with a length of 59 miles, and the crew is adding 3 miles to the roa
AlekseyPX

L = total length

D = number of days

they add 3 miles per day which = 3D

equation:  L = 59 +3D

 if they worked for 34 days, replace D with 34 to get:

L = 59 +3(34) =

L=59 + 102

L=161 miles total length after 34 days

5 0
4 years ago
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