- Let r represent Rick’s height.
- Therefore, the quotient of Rick’s height and 4
![= \frac{r}{4}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7Br%7D%7B4%7D%20)
- Fred is 5 inches shorter than the quotient of Rick’s height and 4.
- Therefore, an expression that represents Fred’s height is
![\frac{r}{4} - 5](https://tex.z-dn.net/?f=%20%5Cfrac%7Br%7D%7B4%7D%20-%205%20)
Answer:
![\frac{r}{4} - 5](https://tex.z-dn.net/?f=%20%20%5Cfrac%7Br%7D%7B4%7D%20-%205)
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
x=±![\sqrt{15/2}](https://tex.z-dn.net/?f=%5Csqrt%7B15%2F2%7D)
Step-by-step explanation:
Answer:
<em>42/63 = .6 repeating</em>
<em>30/38 = .625</em>
<em>36/60 = .6</em>
<em>57/90 = .63 repeating</em>
Step-by-step explanation:
Nd if I'm wrong then the 2nd nd 3rd one are switched
Answer:
<em>D.) 0</em>
Step-by-step explanation:
Its not A. cause 2y−2=0 is y = 1
Its not B. cause 2y−1=0 is y = 1/2
Its not C. cause 2y−3=0 is y = 3/2
Soo... The only option left is D.
It IS D. cause 2y − 0 = 0 is y=0
<em>So you are Correct!!!</em>
<em>hope I helped... <3</em>
<em>Good luck dear :)</em>
Answer:
Step-by-step explanation:
We know that if a figure is reflected across y axis then its y coordinate remains same but the x coordinate changes its polarity.
i.e. the function
will become
.
Now, the given function :
Then , after reflection across y axis the new function will become: