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4 years ago

Which is not equvilent to 5/6 ? 10/12 , 13/14 , 15/18 , 25/30 explain

2 answers:

7 0

13/14. If you multiply 5/6 by 2 you get 10/12. By 3 is 15/18 and by 5 is 25/30. These can all be simplified down to 5/6, but 13/14 cannot.

mars1129 [50]4 years ago

6 0

10/12 LMF=2 10/12 divided by 2= 5/6
15/18 GMF=3 15/18 divided by 3=5/6
25/30 GMF=5 25/30 divided by 5= 5/6
13/14 has no solution

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers

A population of 1,750 cheetahs decreases by 10% per year. How many cheetahs will there be in the population after 11 years? Roun

Triss [41]

Answer:

The answer is C. 546.

If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.

After 1 year: 1750 * 0.89 ≈ 1558

After 2 years: 1558 * 0.89 ≈ 1387

After 3 years: 1387 * 0.89 ≈ 1234

After 4 years: 1234 * 0.89 ≈ 1098

After 5 years: 1098 * 0.89 ≈ 977

After 6 years: 977 * 0.89 ≈ 870

After 7 years: 870 * 0.89 ≈ 774

After 8 years: 774 * 0.89 ≈ 689

After 9 years: 689 * 0.89 ≈ 613

After 10 years: 613 * 0.89 ≈ 546

Step-by-step explanation:

4 0

3 years ago

The box plots below show the lifespan, in months, of laptop batteries manufactured by four companies:

Kay [80]

Answer:

I think it's company A.

Step-by-step explanation:

It has the longest box

5 0

3 years ago

20. Solve for x. 25 12 20

yawa3891 [41]

Answer:

x = 9.6

Step-by-step explanation:

25x = 12 x 20

25x = 240

x = 9.6

3 0

3 years ago

Please at least do part A and explain! I have no idea how to do it.

Fudgin [204]

Part A:
Round 296 to 300
Round 56% to 60%
60% of 300 is 180
300+180=480 employees

Part B:
56% of 296 is 165.76
296+165.76=461.76

4 0

3 years ago