Question

NO LINKS!! Please help me with this problem​

Answer 1

#1

$\\ \rm\Rrightarrow \dfrac{WX}{GH}=\dfrac{UY}{JI}$

$\\ \rm\Rrightarrow \dfrac{8}{14}=\dfrac{UY}{28}$

$\\ \rm\Rrightarrow \dfrac{8(28)}{14}=UY$

$\\ \rm\Rrightarrow UY=8(2)=16$

#2

$\\ \rm\Rrightarrow \dfrac{UV}{UY}=\dfrac{FJ}{JI}$

$\\ \rm\Rrightarrow \dfrac{UV}{16}=\dfrac{21}{28}$

$\\ \rm\Rrightarrow UV=\dfrac{3}{4}\times 16$

$\\ \rm\Rrightarrow UV=3(4)=12$

#3

$\\ \rm\Rrightarrow \dfrac{WX}{XY}=\dfrac{GH}{HI}$

$\\ \rm\Rrightarrow \dfrac{8}{XY}=\dfrac{14}{35}=\dfrac{2}{5}$

$\\ \rm\Rrightarrow 2XY=40$

$\\ \rm\Rrightarrow XY=20$

Answer 2

Answer:

UY = 16

UV = 12

XY = 20

Step-by-step explanation:

If UVWXY ~ JFGHI

then:

UV~JF

VW~FG

WX~GH

XY~HI

UY~JI

The only pair of sides that both have measures is WX and GH:

WX = 8

GH = 14

⇒ GH/WX = 14/8 = 1.75

Therefore, JFGHI is and enlargement of UVWXY by scale factor 1.75

As IJ = 28

⇒ UY = 28 ÷ 1.75 = 16

As JF = 21

⇒ UV = 21 ÷ 1.75 = 12

As HI = 35

⇒ XY = 35 ÷ 1.75 = 20