Answer:
a) 0.144J
b) 0.12J
Explanation:
A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest. a.) Find the total kinetic energy after collision if the collision is elastic. b.) Find the total kinetic energy after collision if the collision is completely inelastic.
Given that
M1 = 0.2kg
M2 = 0.6kg
U1 = 1.2 m/s
Since both momentum and energy are conserved in elastic collisions, the total kinetic energy after collision will be
1/2M1U^2 + 1/2M2U^2
1/2 × 0.2 × 1.2^2 + 0
K.E = 0.144J
B) In elastic collision, only momentum is conserved
M1U1 + M2U2 = (M1 + M2)V
U2 = 0 since the object is at rest
0.2×1.2 + 0 = (0.2 + 0.6)V
0.24 = 0.8V
V = 0.24/0.8
V = 0.3 m/s
K.E = 1/2(M1+M2)V
K.E = 1/2 (0.2 + 0.6) × 0.3
K.E = 0.4 × 0.3
K.E = 0.12J
Answer:
44.4cm
Explanation:
glass has an index of refraction .n = 1.54
radii of curvature of 40 cm R1 = 40 by
radii of curvature of 600 cm R2 = 60
Now, by lens maker formula
1/f = (n - 1) (1/R1 - 1/R2)
Putting in the given values for n = 1.54 , we get f = 22.2
f = 1 / 0.0225
f = 44.4cm
so, focal length in air will be = 44.4 cm
Answer:
2.
Explanation:
1. would be the strong nuclear force.
3. would be the electromagnetic force.
4. would be gravity.
Answer:
Width of a box,
Explanation:
The ground level energy of a proton in a box is, E = 5 MeV
Energy in a box is given by :
For ground state, n = 1
m is mass of proton
h is Planck's constant
l is width of the box
So, the width of the bx is .
ans) 1.Green House gasses 2. carbon dioxide 3.nitrious gases