Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
V=1/3(base area)(height)
base area=14x14=196
height:9
V=(1/3)(196)(9)
V=588
Brainliest pls, hope this help :)
yes it is right when the vertex of the first polygon is located on 3 - 2 after rotation the work vertex will be there on (2 , 3) it is right
OK here is it
y=mx+c is the basic equation for a linear graph
If u plot the values above on a graph u'll get a straight line so
m is the slope or if they havent taught u slope is amount of y increases or decreases with respect to x. and C is the intercept or in other words where the graph or the system given above meets the y axis.
the above info is quite unnecessary but important to know
so putting the values into the equation
Youll get the values of m and C so
m=-1/2 and C=11
the relation between x and y is
y=(-1/2)x+11
put the values from the table ull get the right answer
Yes, 60° is right.
Do you need me to explain why?