Answer:
9
Step-by-step explanation:
18 + 45 = 63
9 x (2+5) = 9 x 7 = 63
Answer: -36 = 8
Step-by-step explanation:
Answer:
(8,-4)
Step-by-step explanation:
i hope thats right cause im doing that right now too lol
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
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These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
-15/-21 -14/x
-15x = -21 * -14
x = -19.6
answer -14c = -19.6 or about -20
answer 3c = .6 or about 1
formula would be
y= 1.2x -3
partial variation means the line doesn't go through (0,0)