The congruence theorems or postulates that could be given as reasons why ACDE=AOPQ are:
<h3>What is this congruence theorems about?</h3>
Note that in the diagram, there has been given one side that is congruent to its other corresponding side and as such, it has remove the option or postulates that needs the HL and SAS sides.
Conclusively, when all three angles are said to be congruent and when they have one side (known as the hypotenuse), one can use the congruence theorems or postulates of AAS, HA and ASA.
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Answer:
e3y3u
Step-by-step explanation:
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Changes made to your input should not affect the solution:
(1): "x1" was replaced by "x^1". 3 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
x + ((((3•19x2) • x6) • x8) • x12)
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
57x28 + x = x • (57x27 + 1)
Trying to factor as a Sum of Cubes :
3.2 Factoring: 57x27 + 1
Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 57 is not a cube !!
Final result :
x • (57x27 + 1)
Processing ends successfully
Answer:
x³ - 3x² + 10x + 3 +
Step-by-step explanation:
Using synthetic division to divide by x - 1
1 | 1 - 4 13 - 7 3
↓ 1 - 3 10 3
----------------------------
1 - 3 10 3 6 ← remainder = 6
--------------------
↑ quotient
= x³ - 3x² + 10x + 3 +
A reflection across a line is a rigid transformation. Therefore the shape of the original object will not change. Because of this, you know that it would have the same measure as the original angle.