The diagram of the right-angled triangle is shown below
Using the Pythagoras theorem
6² = a²+a²
36 = 2a²
18 = a²
a = √18 = 3√2
Answer:
-5 <3
Step-by-step explanation:
Answer:
99.73% of bags contain between 62 and 86 chips .
Step-by-step explanation:
We are given that the number of chips in a bag is normally distributed with a mean of 74 and a standard deviation of 4.
Let X = percent of bags containing chips
So, X ~ N()
The standard normal z score distribution is given by;
Z = ~ N(0,1)
So, percent of bags contain between 62 and 86 chips is given by;
P(62 < X < 86) = P(X < 86) - P(X <= 62)
P(X < 86) = P( < ) = P(Z < 3) = 0.99865 {using z table}
P(X <= 62) = P( <= ) = P(Z <= -3) = 1 - P(Z < 3)= 1 - 0.99865 = 0.00135
So, P(62 < X < 86) = 0.99865 - 0.00135 = 0.9973 or 99.73%
Therefore, 99.73% of bags contain between 62 and 86 chips .
Answer:
Answer:
y = -5(x - 7)^3 - 1
Step-by-step explanation:
You kind of just plug in the numbers.
a vertical stretch by a factor of 5: y = 5x^3
a reflection across the x-axis: y = -5x^3
a vertical translation 1 unit down: -5x^3 - 1
a horizontal translation 7 units right: -5(x - 7)^3 -1
Step-by-step explanation:
Probability of being defective is 14% = 14/100 = 7/50
P(Both defective) = 7/50 * 7/50 = 49/2500