Answer:
6.81s
Step-by-step explanation:
First you must know that the velocity of the body is zero at the maximum height.
v =dy/dx
v= -32x+218
Since v = 0
-32x+218 =0
32x =218
x= 218/32
x = 6.81s
Hence the rocket reaches its maximum height after 6.81s
Your equation is a little messed up comment me the equation you need help with
First on is linear, second is exponential, third is exponential and the last is linear
All problems that are linear increase by a constant rate, ones that increase exponentially increase by a percentage or decimal
Answer:
C
Step-by-step explanation:
Using Parts Whole Postulate we can write:
∠LQP = ∠LQR + ∠PQR
We know that ∠LQP = 77° and ∠LQR = 35° so we can write:
77° = 35° + ∠PQR
Therefore the answer is 77 - 35 = 42°.