The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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Velocity of the boy at the bottom of the slide</h3>
The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is height of the boy
- g is acceleration due to gravity
v = √(2 x 9.8 x 10)
v = 14 m/s.
Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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Answer:
Gay-Lussac’s law, because as the pressure increases, the temperature increases
Explanation:
First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.
This means that in this situation we can apply Gay-Lussac's law, which states that:
"for a gas kept at constant volume, the pressure of the gas is proportional to the absolute temperature of the gas".
Mathematically:
where p is the pressure in Pascal and T is the temperature in Kelvin.
In this case, the tank is filled with air: this means that the pressure of the gas inside the tank increases. And therefore, according to Gay-Lussac's law, the temperature will increase proportionally, and this explains why the tank gets hot.
Answer:
50.67
Explanation:
L = 4 m
Let the mass of small length dx is dm.
So, dm = ρ(x) dx
Integrate on both the sides within proper limits
m = 40 + 32 / 3 = 152 / 3 = 50.67
Answer:
0.066m
Explanation:
use the formula
velocity= frequency × wave length
344m/s = 5200Hz× wavelength
wavelength = 344m/s/5200Hz
wavelength = 0.066m(to 2 sig fig)
The total momentum is unchanged according to the law of conservation of momentum. When the gun is fired, the bullet gains a high velocity forward (positive velocity), and that velocity multiplied by its mass is the momentum the bullet gains. Therefore, the gun must gain a momentum backwards to cancel out that momentum forward, so the gun recoils back with a negative velocity.