N=0.5/3
i'm like 90% sure if i'm wrong i'm sorry lol
The answer to your question is <em>"A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 2 crosses, Dog has 3 crosses, Rabbit has 1 cross, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners." </em>Because this is the only plot described that fits with the data from the table with the information on how many cats, dogs, rabbits, and guinea pigs there are.
To solve this problem:
The formula would be: New Value – Old Value)/Old Value] x
100 or in the form of variable it would be: [(B-A)/A] x 100 = Answer.
So plugging in the information given in our problem it would
be:
0 – 16 / 16 x 100 = percent of change
0/16 x 100 = 0%
The answer is 0%
Answer:
n+12 <4
Step-by-step explanation:
We need to know the function that models the difference in the number of customers visiting the two stores.
We know the function that models the number of customers in the cafeteria
W (x) = 0.002x3 - 0.01x2
We also know the function that models the number of customers who visit the ice cream parlor
R (x) = x2 - 4x + 13
Therefore the difference, D (x), in the number of customers visiting the two stores is:
D (x) = W (x) - R (x)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - (x ^ 2 -4x +13)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - x ^ 2 + 4x -13
D (x) = 0.002x ^ 3 - 1.01x ^ 2 + 4x -13
<span> The answer is the third option</span>