Answer:
3.55m/s^2
Explanation:
S = ut + 1/2at^2
S = 48m, u = 0, t = 5.2
48 = (0×5.2) + (1/2 × 5.2^2)a
48 = 13.52a
Dividing through by 13.52
a = 48/13.52
a = 3.55m/s^2
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
= (5 * 10) Kg m/s
= 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
Answer:
The diameter of the needle is <u>4.675 cm</u>.
Explanation:
Given:
Volume flow rate is,
Velocity of air expelled by pump is,
Let the area of the needle be 'A' cm² and the diameter be 'd' cm.
We know that, volume flow rate of the air expelled by pump is given as the product of the needle's area and velocity of air flowing through that area.
Therefore, volume flow rate is given as:
Now, considering the needle to be circular, area of the needle can be written as:
Therefore, the diameter of the needle is 4.675 cm.
Solution is in attachment ~
I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~