Answer:
C. 3.00 s
Explanation:
Given:
Δy = 1.80 m − 46.0 m = -44.2 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
-44.2 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 3.00 s
Answer:
the work done by friction is 12 J.
Explanation:
Given;
mass of the car, m = 2 kg
initial speed of the car, u = 4 m/s
final speed of the car, v = 2 m/s
The work done by friction is equal to change in kinetic energy of the car,
W = ΔK.E
W = ¹/₂m(v² - u²)
W = ¹/₂ x 2 (2² - 4²)
W = -12 J (the negative sign indicates that it is a wasted energy)
Therefore, the work done by friction is 12 J.
Answer:
0.003060 cm³
Explanation:
Mass of water = m = 326.75 gram
Density of water = ρ = 1.00 g/mL = 1 g/cm³
density = mass / volume
⇒volume = density / mass
⇒volume = 1 / 326.75
⇒Volume = 0.0030604 cm³
∴ Volume held by beaker = 0.0030604 cm³
Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.
Hello there!
For this, you'll first need to convert 20km to meters! This way, the units will cancel out to give you time!
So:
distance= ____m
average speed= 4 m/S
time= solve
You'll need to use an equation to solve for time, which requires minimal algebra manipulation. :)
Original equation:
Speed= distance/time
Hint: Multiply both sides by time first, then go from there!
So, do some simple algebraic manipulation to get time. :)
The simply plug in your values to get the answer!
My goal is to make sure you understand the problem, which is why I'm not going to do the work for you. It'll be more work now, but less work in the future! :)
Hope this helped!!
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DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!