Question

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Answer 1

We have this table

$\begin{array}{|c|c|c|c|c|}\cline{1-5}\text{outcome}&A&B&C&D\\ \cline{1-5}\text{frequency}&20&11&14&30\\ \cline{1-5} \end{array}$

The values in the bottom row add to 20+11+14+30 = 75, so that matches up with the fact that the spinner was spun 75 times. Of those 75 spins, 11+14 = 25 landed on either B or C.

So 25/75 = 0.33 is the approximate experimental probability of landing on B or C.

Answer: Choice A) 0.33