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pashok25 [27]
4 years ago
13

Need help with this math

Mathematics
1 answer:
mafiozo [28]4 years ago
6 0

Solution

Leased cost for 3 years  = $3000 + 250 *36                    [ 3 years = 36 months]

= 3000 + 9000

Leased the car for 3 years cost you = $12,000

The residual value = $10,000

Assume that you bought the car and used for 3 years and sold for $10,000

Cost of the car = $24,000

Sold after 3 years for $10,000

Your expense in 3 years = $24,000 - 10, 000 = $14,000

By comparing these two options, leasing the car will benefit you since it cost only $12,000.

Therefore, lease car is less expense.

The cost for buying the car and selling it after three years would be $14,000.

That is the answer. :)

Thank you.

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The reciprocal of 4 1/3 is
blsea [12.9K]

Answer:

3/13

Step-by-step explanation:

First you need to  know what a reciprocal is. Is the fraction flipped.

Steps:

1. turn 4 1/3 into an improper fraction

         4x3 +1 = 13

           13/3

2. Flip it

            13/3 ---> 3/13

Hope that helped!

5 0
3 years ago
A local little league has a total of 85 players, of whom 20% are right-handed how many right-handed players are there?
Nadusha1986 [10]

Twenty percent of eighty-five is seventeen.

5 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
motikmotik

Answer:

B

Step-by-step explanation:

The answer to the equation is 5.333333333, so I rounded it to 5 1/3

5 0
3 years ago
Read 2 more answers
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
Anne and Willow are reading the copy of the same magazine for an assignment.
Kamila [148]

Answer:

Page number 74

Step-by-step explanation:

Let

x ---> the number of days

y ---> the number of pages read

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

<em>Anne</em>

The slope is equal to

m=20\ \frac{pages}{day}

The y-intercept is equal to

b=14\ pages

substitute

y=20x+14 ----> equation A

<em>Willow</em>

The slope is equal to

m=22\ \frac{pages}{day}

The y-intercept is equal to

b=8\ pages

substitute

y=22x+8 ----> equation B

equate equation A and equation B

22x+8=20x+14

solve for x

22x-20x=14-8\\2x=6\\x=3\ days

Find the value of y

substitute the value of x in equation A or equation B

equation A

y=20(3)+14=74\ pages

equation B

y=22(3)+8=74\ pages

7 0
3 years ago
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