Answer:
The height is 80 meters.
Explanation:
The equation for the distance in the second segment of the fall is as below. In it, we use the initial velocity v1 that the ball had after completing the first segment. From this equation, v1 can be determined:
Next, we use the kinematic equation for velocity at the end of the first segment of a free fall, to determine h1:
The total height is then
Answer:
The maximum compression of the spring after the collision is 0.15 m
Explanation:
Given data
Mass of the block (m) = 0.80 kg
Initial velocity (v) = 1.2 m/s
Spring constant (k) = 50 N/m
Find the maximum compression of the spring (x) after compression
Potential energy of the spring = Kinetic energy of the block
Kinetic energy of the block = 0.5 × (mv)²
Kinetic energy of the block = 0.5 × (0.80 × 1.2)²
Kinetic energy of the block =0.5 × 0.9216
Kinetic energy of the block = 0.4608 ---------->(1)
Potential energy of the spring = 0.5 × k × x²
Potential energy of the spring = 0.5 × 50 × x²
Potential energy of the spring = 25 x² ---------> (2)
Equate (1) and (2)
25 x² = 0.4608
x² = 0.018432 m²
x =0.1357 = 0.15 m
Therefore the maximum compression of the spring after collision is 0.15 m
The answer will be v=16.7m/s
I hope this helps you, have a great day!
Speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser is 0.127 m / s
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 27 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8)
= 286.62× = 2866N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2866 * π * (0.2 / 2) ^ 2 = 0.089N
As, a = F / m
a = 0.089 / 104 = 0.00085m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.00085 * 106
V = 0.127 m / s
The complete question is: You've recently read about a chemical laser that generates a 20.0-cm-diameter, 27.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20.0-cm-diameter, 104 kg, perfectly absorbing block. What speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser? Express your answer with the appropriate units.
The orbit of a space shuttle is surprisingly like an apple falling from a tree to earth. The space shuttle is simply moving so fast that the path of its fall is an orbit around our planet. Which of Newton’s laws helps explain the orbit of a space shuttle around earth and the orbit of earth around the sun