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4 years ago

Find the difference 2/3 and -3/4

Mathematics

2 answers:

kenny6666 [7]4 years ago

6 0

2/3 - (-3/4)=

8/12 - (-9/12)=

8/12+9/12=

17/12

astra-53 [7]4 years ago

5 0

The answer would be -1/12 .
2/3 - -3/4=-1/12
2/3=8/12
-3/4=-9/12
8/12- -9/12=-1/12

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an algebraic expression to represent the new x-coordinate after a translation of two yards east given any initial x-coordinate,

Deffense [45]

Answer:

The required expression is (x+2).

$x'=x+2=3+2=5$

Step-by-step explanation:

The given point is (3,6).

Here,

x-coordinate = 3

y-coordinate = 6

We need to find an algebraic expression to represent the new x-coordinate after a translation of two yards east.

If a point is shift 2 yard east it means the value of x-coordinate increases by 2 units. It means

$x'=x+2$

where, x' is new x-coordinate and x is initial x-coordinate.

Put x=3 in the above equation.

$x'=3+2=5$

Therefore, the new x-coordinate is 5.

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3 years ago

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sveta [45]

To solve this problem, we need to know the formula of the surface area of a triangular prism. The formula is: A = 2 $A_{B}$ + (a+b+c) * h

Now we can substitute values and solve

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3 years ago

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Pavlova-9 [17]

Answer:

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3 years ago

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Marta_Voda [28]

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3 years ago

Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the air

mr Goodwill [35]

Using the <em>normal probability distribution and the central limit theorem</em>, it is found that the probability is of 0.9974 = 99.74%, which means that the pilot should take action.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, for the population, the mean and the standard deviation are given by, respectively:

$\mu = 185.47, \sigma = 39$ .

For a sample of 37 passengers, we have that:

$n = 37, s = \frac{39}{\sqrt{37}} = 6.4116$

The probability that the aircraft is overloaded is <u>one subtracted by the p-value of Z when X = 167.6</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{167.6 - 185.47}{6.4116}$

$Z = -2.79$

$Z = -2.79$ has a p-value of 0.0026.

1 - 0.0026 = 0.9974.

There is a 0.9974 = 99.74% probability that the aircraft is overloaded. Since this is a very high probability, the pilot should take action.

To lern more about the <em>normal probability distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0

2 years ago