Answer:
Not reasonable.
Step-by-step explanation:
Hello!
You have two samples from normally distributed variables. Let's say:
Sample 1
X[bar]₁= 485.6
S₁= 44.3
n₁= 49
Sample 2
X[bar]₂= 390.1
S₂= 61.3
n₂= 31
A Student-t distribution is graphically almost identical to a normal distribution. This distribution is defined as:
Where Z is variable with normal distribution and V is a variable with chi-square distribution and Z and V are independent variables.
This is the reason why the distribution looks so much like a normal distribution and, as the sample sizes grow, it tends to be identical to the normal distribution.
Depending on the criteria of the statistics course you are taking, it is the sample size from which you stop choosing to use the student's t and you start using the normal distribution. In general, with n greater than 20 or 30 the normal approximation is already used.
Applying these criteria, since n₁ and n₂ are bigger than 30 I wouldn't recommend using the pooled t-test.
I hope it helps!
In general.,Cary’s claim is sometimes true, but in this particular expression Cary’s claim is always true
Step-by-step explanation:
The given expression is −5+m−5+m
(-5) +(-5) = -10 and m+m = 2m
= -10+2m it is a negative expression
in mathematical addition (+) + (-) = - (minus) or negative
In general.,Cary’s claim is sometimes true, but in this particular expression Cary’s claim is always true
Answer:
B
Step-by-step explanation:
(x-3)² + (y-2)² = 16
(x-h)²+(y-k)²=16
r=4
h=3
k=2
center is at the point (h, k) ⇒ (3, 2)
Answer:
The rules which could describe the rotation is, 90 degree counterclockwise.
Step-by-step explanation:
Given that:
Triangle XYZ with vertices X(0,0), Y(0, -2) and Z(-2, -2) is rotated to create the image triangle X'(0,0) , Y'(2, 0) and Z'(2, -2).
The rule of rotation of 90 degree counterclockwise:
Therefore, the rules which could describe the rotation is, 90 degree counterclockwise.
Answer:
Option: C is the correct answer.
C. Periodic with period 4 and amplitude of about 15.
Step-by-step explanation:
We are given the table of values as:
Hour 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11
Number 24-41-10-32-26-38-9-31-25-39-12
of boats
As we could see that after every 4 value the values are approximately repeating.
Hence,the data set is approximately periodic.
Also, the amplitude is calculated as:
Average of the maximum and minimum value of each set
We divide the set into 3 sets as follows:
Hour 1 2 3 4
Number of boat 24 41 10 32
Here we have amplitude as:
(41-10)/2=15.5
Hour 5 6 7 8
Number of boat 26 38 9 31
Amplitude is:
(38-9)/2=14.5
Hour 9 10 11 12
Number of boat 25 39 12
Amplitude is:
(39-12)/2=13.5
Hence, we see that the amplitude is about 15.