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Ilya [14]
3 years ago
10

64/7 as a mixed number

Mathematics
2 answers:
masya89 [10]3 years ago
6 0
9 and 1/7
You can just look it up on the internet. 
Kruka [31]3 years ago
6 0

Answer:

Step 1 - Find Whole Number

Calculate out how many times the denominator goes into the numerator. To do that, divide 64 by 9 and keep only what is to the left of the decimal point:

64 / 9 = 7.1111 = 7

Step 2 - Find New Numerator

Multiply the answer from Step 1 by the denominator and deduct that from the original numerator.

64 - (9 x 7) = 1

Step 3 - Get Solution

Keep the original denominator and use the answers from Step 1 and Step 2 to get the answer. 64/9 as a mixed number is:

7

   1  

   9  

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
Please someone help me, I will give you brainliest <br><br> Factor the expression: y^2 + y + 1/4
Firdavs [7]

Answer:

y² + y + \frac{1}{4} = (y + \frac{1}{2})²

Step-by-step explanation:

In most cases, we can factor a polynomial, or quadratic, by looking at the factors of the last term.  In this case, the last term is \frac{1}{4}.  When we factor a polynomial, we are looking for two expressions that when multiplied together using FOIL (forward-outside-inside-last) will give us the polynomial.  For example: (a + b)(a + b) or (a+ b)².

In order to get y² + y + \frac{1}{4}, we are looking for a 'c' value that will add up to '1' which is our 'b' value (ay² + by + c).

Since \frac{1}{2}*\frac{1}{2}=\frac{1}{4}and\frac{1}{2}+\frac{1}{2}=1

Then, we can use \frac{1}{2} as our factor for both expressions.  Putting this together we get:  (y + \frac{1}{2})(y + \frac{1}{2}) or (y + \frac{1}{2})²

8 0
3 years ago
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