C. The volume decreases to half of its original value
Answer:
Explanation:
A. The charge on an element is determined by the differences between the number of protons and electrons in an atom.
An atom will have no charges if the number of protons and electrons are the same.
- When an atom loses or gains electrons, the number of electrons will either decrease or increase
- if the number of electrons is more than the number of protons, the excess electrons is the charge on the atom. And this makes the atom become a negatively charged ion.
- if the number of electrons is lesser than the number of protons, the deficient electrons makes the atom a positively charged ion. The number of electrons by which the atom is deficient makes the atom a positively charged ion.
Charge = number of protons - number of electrons
B. Electrons form the charges they do because with the charge, they become stable like the noble gases.
The desire of every atom is to have stable electronic configuration like those of the noble gases.
A potassium atom with a configuration 2 8 8 1 will prefer to lose an electron to become an Argon atom making the ion stable.
An arithmetical operator used for converting a quantity expressed in a set of unit into an equivalent in another set of units are known as conversion factor.
The base SI units for length is meter, .
The conversion of to other relevant units are as:
So,
Now converting the given units as:
1a.
Since,
So,
2a.
Since,
So,
3a.
4a.
Since,
So,
5a.
6a.
Since,
So,
7a.
8a.
9a.
10a.
Since,
So,
1b.
Since,
So,
2b.
Since,
So,
3b.
4b.
5b.
6b.
7b.
8b.
9b.
10b.
Answer:
Cl < P < Mg < Na
Explanation:
Cl must have the smallest radius because it is located to the right of the remaining elements on the same row. P must have the second smallest radius because it is located to the right of the remaining elements on the same row. Mg must have the Third smallest radius because it is located to the right of Na on the same row. Therefore, Na has the Largest radius.
I hope it helps.
The reaction of removing CO2
using LiOH is the following:
2 LiOH + CO2 -----> Li2CO3
+ H2O
By solving the amount of CO2
the LiOH can scrub:
(3.50 × 10^4 g LiOH) (1 mol LiOH/
24 g LiOH) ( 1 mol CO2 / 2 mol LiOH) ( 44 g CO2 /1 mol CO2) = 32, 083.33 g CO2
it can scrub
<span>Since number of astronaut = 32,
083.33 g / 9 (8.8 × 10^2) = 4 astronaut</span>