Question

Assuming that a rabbit runs at a speed of 12.0 meters per second. How far would the rabbit travel in 11.5 seconds? A hiker takes a hiking trip around the camp. He first travels 5.10 km in one hour at a constant speed. He then travels 16.5 km in two hours at a different constant speed and reaches a ranch tower. What is the average speed of the hiker for the entire trip?

Answer 1

Answer:

(A). The rabbit travel the distance 138 m.

(B). The average speed of the hiker for the entire trip is 7.2 km/h.

Explanation:

Given that,

Speed = 12.0 m

Time = 11.5 second

(A). We need to calculate the distance

Using formula of distance

$d=v\times t$

$d =12.0\times11.5$

$d=138\ m$

The rabbit travel the distance 138 m.

(B). Given that,

Distance = 5.10 km

Time = 1 hours

Distance 16.5 km

Time = 2 hours

We need to calculate the average speed of the hiker for the entire trip

Using formula of average speed

$v=\dfrac{D}{T}$

Where, D = Total distance

T = Total time

Put the value into formula

$v=\dfrac{5.10+16.5}{1+2}$

$v=7.2\ km/h$

The average speed of the hiker for the entire trip is 7.2 km/h.

Hence, This is the required solution.