Answer:
v = 0.028 m/s
Explanation:
In this case you take into account that all the elastic potential of the box, when the spring is compressed is equal to the kinetic energy of the box before it hits the spring. That is:
(1)
m: mass of the box = 4.5kg
k: spring constant = 85N/m
x: compression of the spring = 6.5cm = 0.0065m
You solve the equation (1) for v:
(2)
Next, you replace the values of the parameters:
The velocity of the box when it hits the spring is 0.028m/s
<span>There are two significant figures: 2 and 0 The significant figures of a number are those digits that carry meaning contributing to its precision. Leading zeros (the zero before the 2) are not significant. </span>
Inconsistent. You should take three readings at least.
Answer:
θ = 4.716 10⁻⁶ rad
Explanation:
In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.
We use the diffraction equation for a slit
a sin θ = m λ
The minimum occurs at m = 1
sin θ = λ / a
Since the angles in these systems are very small, we can approximate the sine to its angle in radians
θ = λ / a
The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number
θ = 1.22 λ / a
Let's calculate
θ = 1.22 518 10⁻⁹ / 13.4 10⁻²
θ = 4.716 10⁻⁶ rad