In air, you'd call it air resistance, pilots call it drag. In water, some call it
water resistance, or just plain drag.
Whatever it's called, it's the friction between the object and the fluid, plus
the force needed to push the fluid out of the way to let the object get through.
Answer:
a) Δx₂ = 31*Δt
b) Δx₁ = 977.5 / a
c) a = 23 / Δt
e) Δx₁ = 42.5*Δt
g) Δt = 0.0565 h
i) a = 0.05 m/s²
Explanation:
Given
v₁ = 54 Mi/h
v₂ = 31 Mi/h
a) We apply the formula
Δx₂ = v₂*Δt
⇒ Δx₂ = 31*Δt (Assuming constant speed)
b) We use the formula
v₂² = v₁² - 2*a*Δx₁ ⇒ Δx₁ = (v₁² - v₂²) / (2*a)
⇒ Δx₁ = (54² - 31²) / (2*a)
⇒ Δx₁ = 977.5 / a
c) We use the equation
v₂ = v₁ - a*Δt ⇒ a = (v₁ - v₂) / Δt
⇒ a = (54 - 31) / Δt
⇒ a = 23 / Δt
e) We apply the formula
Δx₁ = v₁*Δt - 0.5*a*Δt²
Δx₁ = 54*Δt - 0.5*(23 / Δt)*Δt²
⇒ Δx₁ = 42.5*Δt
g) If Δx₁ = 2.4 Mi ⇒ 2.4 = 42.5*Δt ⇒ Δt = 0.0565 h
i) If a = 23 / Δt ⇒ a = 23 Mi / 0.0565 h = 407.29 Mi/h²
⇒ a = 0.05 m/s²
H would be the correct answer senate house of rep then congress then president to sign