Using the principle of probability, the likelihood that Shreya wins by getting <em>2 blues and 1 red</em> is 0.416
<u>Creating</u><u> </u><u>an</u><u> </u><u>area</u><u> </u><u>model</u><u> </u><u>for</u><u> </u><u>the</u><u> </u><u>first</u><u> </u><u>two</u><u> </u><u>spinners</u><u> </u><u>:</u>
___ G _ B _ B _ R _R _R
R_RG_RB_RB_RR_RR_RR
R_RG_RB_RB_RR_RR_RR
B_BG_BB_BB_BR_BR_BR
B_BG_BB_BB_BR_BR_BR
B_BG_BB_BB_BR_BR_BR
B_BG_BB_BB_BR_BR_BR
G_GG_GB_GB_GR_GR_GR
G_GG_GB_GB_GR_GR_GR
Creating an area model or tree diagram for the third spinner would result in a sample space of (48 × 12) = 576 combinations.
However, the probability that Shreya would win can be obtained thus :
<u>To win he needs to pick get 2 blues and 1 red</u> in any order :
3! = 3 × 2 × 1 = 6 ways
P(BBR) = 1/3 × 4/8 × 5/12 = 0.0694444
P(winning) = 6 × 0.0694444 = 0.416
Therefore, the probability that Shreya wins is 0.416.
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Answer:
It is impossible to find two points that are both 1 inch and 1.5 inches from the point A simultaneously as shown in the following proof
From segment addition postulate given a point C that is between the points of a segment AB, we have;
AC + CB = AB
Therefore, where AC = 1 inch and CB = 1.5 inches, we have;
AC + CB = 1 inch + 1.5 inches = 2.5 inches ≠ AB = 3 inches
However it is possible to find two points in which one of the points is 1 inch from the point A while the other point is 1.5 inches from the point B
Step-by-step explanation:
Answer:
1/4 times 3.
1/4 of 3.
number of fourths in 3.
Step-by-step explanation:
Answer:
A C E........................ go for it
Step-by-step explanation:
Answer:
22,332
Step-by-step explanation:
Put 6 where t is in the equation and do the arithmetic.
... y = 5500 ln(9·6 +4) = 5500 ln(58) ≈ 22,332