Answer: 1.35, 2.5, 1.8
Step-by-step explanation:
Take the derivative of <em>F</em> :
<em>F(x)</em> = <em>x</em>³ <em>f(x)</em> + 10 → <em>F'(x)</em> = 3 <em>x</em>² <em>f(x)</em> + <em>x</em>³ <em>f'(x)</em>
The tangent line to <em>F(x)</em> at <em>x</em> = 1 passes through the point (1, <em>F</em> (1)) and has slope equal to <em>F' </em>(1) :
<em>F</em> (1) = 1³ <em>f</em> (1) + 10 = 2
<em>F</em> '(1) = 3 • 1² <em>f</em> (1) + 1³ <em>f'</em> (1) = -12
Use the point-slope formula to find the equation of the line:
<em>y</em> - <em>F</em> (1) = <em>F'</em> (1) (<em>x</em> - 1) → <em>y</em> = -12 <em>x</em> + 14
Correct answer: <span>Dot-and-cross-diagram
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Dot-and-cross diagrams are used to represent covalent bonds. The shared electron from one atom is shown as a dot, while the shared electron from the other atom is shown as a cross.
When drawing dot-and-cross diagrams for covalent bonds, you only need to show the electrons in the highest occupied energy level, as only these are involved.