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Harman [31]
3 years ago
10

What is the least number of solution a quadratic system can have

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0
The least number of quadratic system can have is Two real solutions or no real solutions. 
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Monthly, Juan's net earnings are $6,000, and expenses are $5,000. If Juan saves the difference, how much will Juan have saved af
lapo4ka [179]

Answer:

$72,000

Step-by-step explanation:

6000-5000=1000

1000x6 =6000

6000x12=72,000

3 0
3 years ago
Método gráfico 3x+y= 9<br>​
ValentinkaMS [17]

Answer:

Graph the line using the slope and y-intercept, or two points.

Slope: −3

y-intercept:

(0,9)

x y. ( 2nd image)

0 9

3 0

image of graph ( 1st image)

Step-by-step explanation:

Hope it is helpful....

7 0
3 years ago
HELP PLEASE
Free_Kalibri [48]

D.The puppy gains approximately 0.25 pound each week.

<u>x = no. of weeks</u> in f(x) = 0.25x + 1.2

3 0
3 years ago
Read 2 more answers
How do you graph (0,3.5)
bazaltina [42]

Answer:

In a coordinate axis, the horizontal line is called the x-axis, and the vertical line is called the y-axis.

1) Then if you have a point (x, y), to graph this you go at the horizontal axis to find the value x,

2) Starting from the point you already found, now you need to move y units in the vertical axis.

Now we want to graph the point (0, 3.5).

First we need to locate the value 0 in the horizontal axis, this is the point where both axes intersect.

Now we move 3.5 units, because the number is positive, we move 3.5 units upwards.

The graph of the point is shown below.

3 0
3 years ago
Give a combinatorial proof that if n is a positive integer, then
gregori [183]

The Empire is attacking a Rebel base that is stocked with n X-wings and n Y-wings. The Rebels need to build a fleet consisting of n ships (with at least 1 X-wing), to be led by 1 pilot in an X-wing.

There are \binom n1=n ways of picking the leader, and \binom{2n-1}{n-1} ways of building the rest of the fleet, so there's a total of

n\dbinom{2n-1}{n-1}

ways of building such a fleet.

In the other direction, suppose we build a fleet comprising of k X-wings and n-k Y-wings. We have \binom nk ways of picking X-wings and \binom n{n-k} ways of picking Y-wings. Also from the k X-wings we pick 1 to be the leader, which we can do in \binom k1=k ways. So there are

k\dbinom nk\dbinom n{n-k}

ways of building such a fleet. But since

\dbinom nk=\dbinom n{n-k}, we have

k\dbinom nk^2

ways of building the fleet with these specifications. Sum over all possible values of k,

\displaystyle\sum_{k=1}^nk\binom nk^2

4 0
4 years ago
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