Hey there!:
Volume of rainfall = Area X height
Height = 1 in = 0.254 dm
1mile2 = 2.59 X 10⁸ dm²
so 1300 miles² = 3367 *10⁸ dm²
Volume = 0.254 * 3367 * 10⁸ = 855.218 * 10⁸ dm³
Also,
H2SO4 ionizes as :
H2SO4 --> H⁺ + HSO4⁻
Ka1 is very high so it completely dissociates , due to first dissociation [H⁺] = Concentration of H2SO4
HSO4⁻ --> H⁺ + SO₄⁻²
We also consider it as high dissociation :
so each mole of H2SO4 will give 2 moles of H⁺ (proton)
pH = 3.30 = -log[H⁺]
So [H+] = 0.000501 M = 0.000501 moles / L or moles / dm³
Volume = 855.218 * 10⁸dm³
so moles of H+ present in this volume:
= 0.000501 * 855.218 *10⁸ = 4.28* 10⁷moles
So moles of H2SO4 = 4.28 * 10⁷ / 2 = 2.14 * 10⁷ moles
Molecular weight of H2SO4 = 98 g / mol
Mass of H2SO4:
Moles X molecular weight = 98 * 2.14 X 10⁷ grams = 209.72 * 10⁷ grams in kg:
= 2.09 X 10⁶Kg
Hope that helps!
Answer:
In a swimming pool chlorine ion are mix with water, a polar molecule. In this case the pool is a perfect environment for the conductive solution. The reason why, people can be electrocuted is that the hypochlorite is an ion and in the water, it form an ionic compound.
Explanation:
Answer:
The percent yield of this reaction is 42.1 % (option B)
Explanation:
Step 1: Data given
Theoretical yield of beryllium chloride = 10.7 grams
actual yield of beryllium chloride = 4.5 grams
Step 2: Calculate the percent yield for this reaction
Percent yield = (actual yield / theoretical yield) * 100%
Percent yield = (4.5 grams / 10.7 grams ) * 100 %
Percent yield = 42.1 %
The percent yield of this reaction is 42.1 % (option B)
Answer:
The higher the temperature, the faster the particles move, the lower the temperature, the slower.
Answer:
5.20 grams of Br₂
Explanation:
From our previous knowledge;
We understand that:
The number of moles of a given element = mass of the element divided by its molar mass.
Mathematically:
From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.
From the periodic table, the molar mass of Bromine is = 79.9 g/mol
As such, the mass of liquid that partakes is calculated as:
0.065 mol = mass/ 79.9 g/mol
mass = 0.065 mol × 79.9 g/mol
mass of liquid that partakes in the reaction = 5.20 grams of Br₂