1747.2 ml of HNO3 is required to reach methyl orange endpoint.
Explanation:
Number of moles of NaOH solution having 17.5 gram NaOH in 350ml of water.
Atomic weight of NaOH = 40 g/mol
thus number of moles= 17.5/40
= 0.437 moles
Now the molarity of the solution is calculated as
M=n/C
= 0.437/O.35 LITRES
= 1.248 M solution of the base
the molarity of acid is given as 0.25 M of HNO3
From the formula
M1V1=M2V2 we can calculate the volume of HNO3 required to make solution acidic.
1.248*350= 0.25*v2
v2= 1.248*350/0.25
= 1747.2 ml
Thus 1747.2 ml of HNO3 is required.
Conformity can be inappropriate when you’re confirming to do negotiate things. Example smoke cigs
Answer:
<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S
<u></u>
<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in H = 2×2 = 4
- Number of atoms in S = 2×1 = 2
- Number of atoms in O = 1×2 = 2
<em>In product side of equation :-</em>
- Number of atoms in H = 2×2 = 4
- Number of atoms in O = 2×1 = 2
- Number of atoms in S = 2×1 = 2
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
