Factorise x squared 7x 12

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

I hope this helps you

x^2+7x+12

x.x+3x+4x+3.4

(x+3).(x+4)

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Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.

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(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7

Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE

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4 years ago

Read 2 more answers

A manufacturer receives parts from two suppliers. An SRS of 400 parts from supplier 1 finds 20 defective; an SRS of 100 parts fr

jeyben [28]

Answer:

Option C) 0.0602

Step-by-step explanation:

We are given the following in the question:

$x_1 = 20\\n_1 = 400\\x_2 = 10\\n_2 = 100$

Let p1 and p2 be the proportion of all parts from suppliers 1 and 2, respectively, that are defective.

$p_1 = \dfrac{x_1}{n_1} = \dfrac{20}{400} = 0.05\\\\p_2 = \dfrac{x_2}{n_2} = \dfrac{x_2}{n_2} = \dfrac{10}{100}= 0.1$

First, we design the null and the alternate hypothesis

$H_{0}: p_1 = p_2\\H_A: p_1 \neq p_2$

We use Two-tailed z test to perform this hypothesis.

Formula:

$\text{Pooled P} = \dfrac{x_1+x_2}{n_1+n_2}\\\\Q = 1 - P\\\\Z_{stat} = \dfrac{p_1-p_2}{\sqrt{PQ(\frac{1}{n_1} + \frac{1}{n_2})}}$

Putting all the values, we get,

$\text{Pooled P} = \dfrac{20+10}{400+100} = 0.06\\\\Q = 1 - 0.06 = 0.94\\\\Z_{stat} = \dfrac{0.05-0.1}{\sqrt{0.06\times 0.94(\frac{1}{400} + \frac{1}{100})}} = -1.883$

Now, we calculate the p-value from the table at 0.05 significance level.

P-value = 0.0602

Thus, the correct answer is

Option C) 0.0602

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