Answer:
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Let the three consecutive integers be x, x+1 and x+2.
According to the question, x+x+1+x+2=51
=>3x+3=51
=>3x+3-3=51-3
=>3x=48
=>x=16
Hence, first integer = 16,
second integer = 16 + 1 = 17 and
third integer = 16 + 2 = 18.
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The cuboid on the left has a volume of
.. (11 yd)*(5 yd)*(2 yd) = 110 yd^3
The cuboid at upper left has a volume of
.. (10 yd)*(4 yd)*(2 yd) = 80 yd^3
The total volume is (110 +80) yd^3 = 190 yd^3.