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loris [4]
4 years ago
9

Hexanal would be soluble in water? True or false?

Chemistry
1 answer:
telo118 [61]4 years ago
5 0

Answer:

False.

Explanation:

Hexanal is a non-polar compound while water is a polar solvent.

We have the role "Like dissolves like".

So, hexanal is insoluble in water.

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Analytical chemistry has two branches, _____, that are important to forensic chemistry. qualitative and quantitative qualitative
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Answer:

qualitative and quantitative

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What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of
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Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

where;

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the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

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molality = \dfrac{mole \ of \ solute }{kg \ of \ solvent }

which can now be re-written as :

molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \  water}

molality = \dfrac{\dfrac{mass \ of \  \ Ca(NO_3)_2}{molar \  mass of \ Ca(NO_3)_2} }{kg \ of \  water}

molality = \dfrac{\dfrac{11.3 \ g }{164 \ g/mol} }{0.115 \ kg }

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∴

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)

\Delta T =3.34^0 \ C

\Delta T = the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

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