The answer would be 14

Explanation:
If you look on a number line and start from 15 then from there you minus 6 which equals 9 then you minus 5 which equals 4 and add 10 which equals 14 and that 14 is on the positive side of the number line. So 14 is your answer.

5 0

4 years ago

Four football fans took turns driving the distance from new York to Oklahoma to see a big game

Snezhnost [94]

I'm sorry but what's the full question?

4 0

4 years ago

What is the slope of the line that passes through the points (1,1) and(-1,-5)

bija089 [108]

$\frac{2}{ - 6}$

5 0

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$

3 0

3 years ago