Hey There!:
Molar mass O2 => 32.0 g/mol
Molar mass Cl2 => 71.0 g/mol
effusion rate α 1 / (√ molar mass )
E Cl2 / E O2 = √ molar mass O2 / √ molar mass Cl2
E Cl2 / E O2 = ( √ 32.0 ) / ( √ 71.0 )
=> 0.671
Hope that helps!
We have to calculate amount of zinc formed in the given reaction.
The amount of zinc formed is 16.47 g.
The balanced chemical reaction between copper and zinc nitrate is as follows:
2Cu (s) + Zn(NO₃)₂ (aq) → Zn (s) + 2CuNO₃ (aq)
From the reaction it is clear that one mole Zn is produced from two moles of Cu.
Atomic mass of copper is = 63.5 g and atomic mass of zinc is = 65.38 g.
As per reaction, 2 X 63.5 g= 127 g of copper produces 65.389 g of zinc. Therefore 32 g copper will produce g = 16.47 g of zinc.
Answer:A. It represents a synthesis reaction because two reactants for one product.
Explanation:
Answer:
241
Explanation:
all the numbers are significant but since you only need three it's only the first three numbers
I can’t read it can you put some light please?