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Answer:
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 170cm and standard deviation of 7.5 cm.
This means that
Find the probability that a randomly selected male has a height > 180 cm.
This is 1 subtracted by the pvalue of Z when X = 180. So
has a pvalue of 0.9082
1 - 0.9082 = 0.0918
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:
Substitute: