FIND THE AVERAGE
WHICH IS 6.11 OR 6
FIND THE DISTANCE OF EACH VALUE FROM 6:
17, 23, 8, 20, AND 12
ADD ALL OF THOSE NUMBERS AND DIVIDE BY 6
MEAN DEVIATION = 13.33 OR 13 3/9
Sorry for the caps
:P hope this helps you
Answer:
(a)
Step-by-step explanation:
Given
See attachment for sets A and B
Required
The true statement about both sets
First, we calculate the typical values (mean) of set A and set B.
This is calculated as:
For A:
For B:
<em>Here, we can conclude that B has a larger typical value</em>
Next calculate the spread (range) of sets A and B
This is calculated as:
For A:
For B
<em>Here, we can conclude that A has a larger spread.</em>
<em></em>
<em>Hence, (a) is true</em>
Answer:
because in the bottom eqution it shows us x-3=y therefor we could re-write the top equation as x+x-3=11
Answer:
B.
Step-by-step explanation:
Option B is correct - angle ABE is less than 90 degrees, therefore it is acute, and angle DBC is greater than 90 degrees, therefore it is obtuse.
Well the real answer is three hundred-ninety three point five. So numbers around it could be three hundred and fifty and four hundred. An estimate could be three hundred and seventy five.
