Answer:
yes it is
Step-by-step explanation:
since 25 is less than 26
The answer is b ok have fun
Answer:
ln(3x)-x²/2 + x +c
Step-by-step explanation:
∫(2x-1) ln (3x) dx can be computed with parts. The ln part can be made simpler be derivating, and integrating a polynomial wont hurt us that much.
We can derivate ln(3x) using the chain rule, the derivate of ln(x) is 1/x and the derivate of 3x is 3; therefore
(ln(3x))' = (1/3x)*3 = 1/x
A primitive of (2x-1) is, on the other hand, x²-x
Hence
∫(2x-1) = ln(3x) (x²-x) - ∫(x²-x)/x dx = ln(3x) (x²-x) - ∫(x-1) dx = ln(3x) (x²-x) - (x²/2 - x + k) = ln(3x)-x²/2 + x +c
Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
__
Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
Answer:
<h2>The determinant is 1</h2>
Step-by-step explanation:
Given the 3* 3 matrices , to compute the determinant using the first row means using the row values [0 4 1 ] to compute the determinant. Note that the signs on the values on the first row are +0, -4 and +1
Calculating the determinant;
The determinant is 1 using the first row as co-factor
Similarly, using the second column as the cofactor, the determinant will be expressed as shown;
Note that the signs on the values are -4, +(-3) and -3.
Calculating the determinant;
The determinant is also 1 using the second column as co factor.
<em>It can be concluded that the same value of the determinant will be arrived at no matter the cofactor we choose to use. </em>