Answer:
the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Explanation:
Given the data in the question;
sound intensity reduced by the factor, m = 305
the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB
Now, using the expression of sound intensity level;
L = 10log( )
where is the intensity at L level
so we substitute
79 = 10log( )
=
Now, expression for actual intensity;
= m
where is the actual intensity
so we substitute
= 305 ×
Next, we write the expression of sound intensity level for reduced intensity;
L' = 10log( )
So we substitute
L' = 10log( 305 × )
L' = 10log( 24227011159.09058 )
L' = 103.8 dB
Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Answer:
B
Explanation:
Laboratories are usually controlled: however, in public places, there are way too many factors that could change an experiment
C because it does depend on both rather than none or just one
Answer:
Hello There!
It is Speed.
Because in the question it is said that at which speed car is travelling.
Speed is a scalar quantity.
If it is velocity then first know this that it is a vector quantity.
It must include both magnitude and direction.
If it is velocity then it would be 40 mph east or west or north or south.
<h2>I hope it is helpful to you...</h2><h3>Cheers!_____________</h3>