Answer:
Step-by-step explanation:
We want to model the position of the submarine as a function of time.
Notice that we have a constant amount. The initial depth: 750 meters
Then we have a factor that varies over time. Every hour the submarine ascends 50 meters. therefore as t increases the depth y(t) of the submarine decreases. Then the factor is:
-50t.
Where t represents the time in hours.
Then the equation that represents the new position of the submarine in relation to the level of the sea:
Answer:
4.32 = k
Step-by-step explanation:
8/k = 5/2.7
We can solve using cross products
8* 2.7 = 5k
21.6 = 5k
Divide each side by 5
21.6/5 = k
4.32 = k
Angles 1 and 2 would be acute and vertical
You start at 18 feet, go down to -14, go down 4 feet to -18 feet or C