(2(3))^2 + 5
2(3) = 6
6^2 = 36
36+5 = 41
Answer: 41
Answer:
89.8 feet
Step-by-step explanation:
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.
We would solve the above question using Sine rule
The formula is given as:
DB/sin D = BC/sin B
93/sin 90 = BC/sin 75
We cross multiply
sin 90 × BC = 93 × sin 75
BC = 93 × sin 75/sin 90
BC = 89.83 feet
Approximately BC = 89.8 feet
<u>Answer</u>
4.71 cm²
<u>Explanation</u>
Area of a circle = πr²
Where r is the radius of the circle.
For a sector which is part of a circle, its area is given by;
Area of a sector = (Ф/360)πr²
where Ф is the angle making the sector at the center of the circle.
∴ Area of a sector = (Ф/360)πr²
= 60/360 × π × 3²
= 1/6 × π × 9
= 4.71 cm²
Answer:
7+12+2=21
Step-by-step explanation:
This what it should look like. did you need the steps or no ?