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gulaghasi [49]
4 years ago
11

A rectangular field is four times as long as it is wide. If the perimeter of the field is 550 feet, what are the dimensions of t

he field? A) Write an equation you can use to answer the given question. Let w be the width of the field.
Mathematics
1 answer:
ad-work [718]4 years ago
4 0

Answer:

The equation used to find length and width is: 550 = 2(4w+w)

Length = 220 feet

Width = 55 feet

Step-by-step explanation:

Let width = w

Length = 4w

Perimeter = 550 feet

We know that Perimeter of rectangle is

Perimeter of rectangle = 2(length + width)

Putting values of length and width

Perimeter of rectangle = 2(length + width)

550 = 2(4w+w)

550 = 2(5w)

550 = 10 w

=> w = 550/10

w = 55

So, width is 55 feet

Now, finding length:

Length = 4w

Length = 4(55)

Length = 220 feet

So, The equation used to find length and width is: 550 = 2(4w+w)

Length = 220 feet

Width = 55 feet

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use the formula A=LW to find the length of a rectangle when the width is 29 yards and the are is 1,044 square yards. Help please
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A = L × W

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<h3><u /></h3><h3><u>Solution:</u></h3>

Divide both sides by W to isolate L:

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