Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
Answer:
5106.38 Ω
Explanation:
From the question given above, the following data were obtained:
Current (I) = 0.0235 A
Voltage (V) = 120 V
Resistor (R) =?
From ohm's law,
V = IR
Where:
V => is the voltage.
I => is the current
R => is the resistor
With the above formula, we can obtain the size of the resistor needed as follow:
Current (I) = 0.0235 A
Voltage (V) = 120 V
Resistor (R) =?
V = IR
120 = 0.0235 × R
Divide both side by 0.0235
R = 120 / 0.0235
R = 5106.38 Ω
Thus, the size of the resistor needed is 5106.38 Ω
Answer:
0.100 M AlCl₃
Explanation:
The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:
ΔT = W.i
Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.
i = final particles/initial particles
C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;
AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;
NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;
MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.
So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.
Below is the structure of 3-Methylpentane. The word pentane in name specifies the parent chain which ends on -ane (alkane) and pent- shows number of carbon atoms is parent chain (pent=5). The position of substituent is specified at the start i.e. 3.
