Answer:
The two column proof can be presented as follows;
Statement 
Reason
1. RUST is a rectangle Given
2. RU = ST ; UT = RS Definition of a rectangle
3. ∠STU and ∠SRU are right angles Definition of a rectangle
4. ΔURS ≅ ΔSTU By SAS rule of congruency
5. ∠USR = ∠SUT By CPCTC
Step-by-step explanation:
Given that the side RU, the angle ∠SRU and the side RS of triangle ΔURS are congruent to the side ST the angle ∠STU and the side UT of triangle ΔSTU, then ΔURS is congruent to ΔSTU, by the Side-Angle-Side (SAS) rule of congruency
Therefore, we have that ∠USR ≅ ∠SUT and therefore, it can be shown that ∠USR = ∠SUT using the Congruent Parts of Congruent Triangle are Congruent (CPCTC) postulate.
Answer:
So total cost of tickets = $64
Step-by-step explanation:
Given:
Cost of adult = $12
Cost of Children = $7
Total Adults = 3
Total children = 4
To Find:
Total Cost = ?
Solution:
We are given per person price and no of persons too now
Total cost = Cost of children ticket + Cost of Adults ticket
Now we will find the values
Cost of 3 adults ticket = total person * cost per person
= 3 * 12
=$36
Cost of 4 Children ticket = total person * cost per person
= 4 * 7
=$28
Now
Total cost = Cost of children ticket + Cost of Adults ticket
putting value
Total cost = 28 + 36
= $ 64
So total cost of tickets = $64
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Answer:
112 ( 14 − 6 ) − ( −4 ) ?= −59
900 ≠ −59
False
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solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
Answer:
2:35 pm
If an hour is 60 minutes, what we know is that 30 minutes is half. However, we must subtract 55 from 30 (In time)
To make this easier, subtract 55 by actual 30, and split 55 into 2 parts, the result of subtraction, and the other value, 30
Now, subtract.
If this is the case, the lesson must have started at 2:35 pm
